WebStep 1: Check which of the equation passes through (2,-1). The solution should satisfy the appropriate equation. So, let us investigate each option by substituting x=2 & y=−1 (A) x+2y=0. L.H.S. =2+2×(−1)=0= R.H.S. ∴ It is the appropriate equation. (B) x+2y=4 L.H.S. =2+2×(−1)=0 = R.H.S. ∴ It is not the appropriate equation. (C) 2x+y=0 WebAnswer: If (6,k) is a solution of the equation 3x + y - 22 = 0, then the value of k is 4. Let us proceed step by step. Explanation: According to the given equation : 3x + y = 22. Since …
If x = 2 is a solution of the equation x^2 - 5x + 6k = 0 , the value …
WebIn mathematics, a set of simultaneous equations, also known as a system of equations or an equation system, is a finite set of equations for which common solutions are sought. Quadratic Formula In elementary algebra, the quadratic formula is a formula that provides the solution (s) to a quadratic equation. WebSolution If x = 3 and y = 4 is a solutions of the equation 5x - 3y = k, so put x=3 and y=4 in equation 5 (3)-3 (4)=k 15-12=k 3=k Suggest Corrections 3 Similar questions Q. Find the value of k if x=3 and y=2 is a solution of the equation 5x+3y−k=0. Q. If x= 2 and y= 3 is a solution of 2x - 3y+ k = 0 find k value and write the resultant equation Q. etihad airways sharjah office
If (2, 0) is a solution of linear equation 2x + 3y= k then the value …
Web28 feb. 2024 · The solution method we use is called separation of variables. We assume that u(x, t) can be written as a product of two other functions, one dependent only on position x and the other dependent only on time t. That is, we make the ansatz u(x, t) = X(x)T(t). Whether this ansatz will succeed depends on whether the solution indeed has … WebWhen given the pH value of a solution, solving for Ka requires the following steps: Set up an ICE table for the chemical reaction. Solve for the concentration of H 3O + using the equation for pH: [H3O +] = 10 − pH Use the concentration of H 3O + to solve for the concentrations of the other products and reactants. Web1 x ( t) = k should give you x ′ ( t) = 0. Also plug in x ( t) = k, so the differential equation becomes − 2 k + 4 = 0 Then you can find k. Share Cite Follow answered Jan 24, 2016 at 0:57 KittyL 16.7k 3 25 53 Add a comment 0 If x ( t) = k is a solution, then x ′ ( t) = 0 (not 1, as you wrote). Then you want to solve − 2 x + 4 = 0 for x ( t) = k. firestone in long beach